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add a way
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same_element_in_list.md

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@@ -35,4 +35,11 @@
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no_repeat = no_repeat_element(el_num)
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print no_repeat
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#解决(python)
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无重复元素个数统计,只有新数组输出
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list_a = [1,1,2,2,2,3,3,3,3,3,]
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list_b = list(set(list_a))
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##qiwsir#gmail.com (# to @)

same_element_in_list.py

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@@ -17,10 +17,22 @@ def no_repeat_element(element_number): #element_number是count_element(one_
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no_repeat_list = [key for key in element_number]
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return no_repeat_list
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"""
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另外一种删除重复元素方法
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list_a = [1,1,2,2,2,3,3,3,3,3,]
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list_b = list(set(list_a))
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"""
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if __name__=="__main__":
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ls = ["a","a","b","b",'b','c','c']
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el_num=count_element(ls)
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print el_num
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no_repeat = no_repeat_element(el_num)
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print no_repeat
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print "another way is:"
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no_repeat2 = list(set(ls))
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print no_repeat2

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