another probelm fix

Author: Pierian-Data

03-Methods and Functions/.ipynb_checkpoints/03-Function Practice Exercises-checkpoint.ipynb

@@ -328,11 +328,13 @@
    "cell_type": "markdown",
    "metadata": {},
    "source": [
-    "#### LAUGHTER: Write a function that counts the number of times a given pattern appears in a string, *including overlap*\n",
+    "### Find 33: \n",
     "\n",
-    "    laughter('hah','hahahah') --> 3\n",
+    "Given a list of ints, return True if the array contains a 3 next to a 3 somewhere.\n",
     "\n",
-    "Note that `'hahahah'.count('hah')` only returns 2."
+    "    has_33([1, 3, 3]) → True\n",
+    "    has_33([1, 3, 1, 3]) → False\n",
+    "    has_33([3, 1, 3]) → False"
    ]
   },
   {
@@ -343,7 +345,7 @@
    },
    "outputs": [],
    "source": [
-    "def laughter(pattern,text):\n",
+    "def has_33(pattern,text):\n",
     "    pass"
    ]
   },
@@ -356,7 +358,7 @@
    "outputs": [],
    "source": [
     "# Check\n",
-    "laughter('hah','hahahah')"
+    "has_33([1, 3, 3])"
    ]
   },
   {

03-Methods and Functions/.ipynb_checkpoints/04-Function Practice Exercises - Solutions-checkpoint.ipynb

@@ -454,11 +454,13 @@
    "cell_type": "markdown",
    "metadata": {},
    "source": [
-    "#### LAUGHTER: Write a function that counts the number of times a given pattern appears in a string, *including overlap*\n",
+    "### Find 33: \n",
     "\n",
-    "    laughter('hah','hahahah') --> 3\n",
+    "Given a list of ints, return True if the array contains a 3 next to a 3 somewhere.\n",
     "\n",
-    "Note that `'hahahah'.count('hah')` only returns 2."
+    "    has_33([1, 3, 3]) → True\n",
+    "    has_33([1, 3, 1, 3]) → False\n",
+    "    has_33([3, 1, 3]) → False"
    ]
   },
   {
@@ -469,12 +471,16 @@
    },
    "outputs": [],
    "source": [
-    "def laughter(pattern,text):\n",
-    "    out = 0\n",
-    "    for x in range(len(text)-2):\n",
-    "        if text[x:x+len(pattern)] == pattern:\n",
-    "            out += 1\n",
-    "    return out"
+    "def has_33(nums):\n",
+    "    for i in range(0, len(nums)-1):\n",
+    "      \n",
+    "      # nicer looking alternative in commented code\n",
+    "      #if nums[i] == 2 and nums[i+1] == 2:\n",
+    "    \n",
+    "      if nums[i:i+2] == [2,2]:\n",
+    "        return True  \n",
+    "    \n",
+    "    return False"
    ]
   },
   {
@@ -495,7 +501,7 @@
    ],
    "source": [
     "# Check\n",
-    "laughter('hah','hahahah')"
+    "has_33([1, 3, 3])"
    ]
   },
   {
@@ -983,7 +989,9 @@
    "cell_type": "markdown",
    "metadata": {},
    "source": [
-    "### Just for fun:\n",
+    "-----\n",
+    "### Just for fun, not a real problem :)\n",
+    "\n",
     "#### PRINT BIG: Write a function that takes in a single letter, and returns a 5x5 representation of that letter\n",
     "    print_big('a')\n",
     "    \n",

03-Methods and Functions/03-Function Practice Exercises.ipynb

@@ -328,11 +328,13 @@
    "cell_type": "markdown",
    "metadata": {},
    "source": [
-    "#### LAUGHTER: Write a function that counts the number of times a given pattern appears in a string, *including overlap*\n",
+    "### Find 33: \n",
     "\n",
-    "    laughter('hah','hahahah') --> 3\n",
+    "Given a list of ints, return True if the array contains a 3 next to a 3 somewhere.\n",
     "\n",
-    "Note that `'hahahah'.count('hah')` only returns 2."
+    "    has_33([1, 3, 3]) → True\n",
+    "    has_33([1, 3, 1, 3]) → False\n",
+    "    has_33([3, 1, 3]) → False"
    ]
   },
   {
@@ -343,7 +345,7 @@
    },
    "outputs": [],
    "source": [
-    "def laughter(pattern,text):\n",
+    "def has_33(pattern,text):\n",
     "    pass"
    ]
   },
@@ -356,7 +358,7 @@
    "outputs": [],
    "source": [
     "# Check\n",
-    "laughter('hah','hahahah')"
+    "has_33([1, 3, 3])"
    ]
   },
   {

03-Methods and Functions/04-Function Practice Exercises - Solutions.ipynb

@@ -454,11 +454,13 @@
    "cell_type": "markdown",
    "metadata": {},
    "source": [
-    "#### LAUGHTER: Write a function that counts the number of times a given pattern appears in a string, *including overlap*\n",
+    "### Find 33: \n",
     "\n",
-    "    laughter('hah','hahahah') --> 3\n",
+    "Given a list of ints, return True if the array contains a 3 next to a 3 somewhere.\n",
     "\n",
-    "Note that `'hahahah'.count('hah')` only returns 2."
+    "    has_33([1, 3, 3]) → True\n",
+    "    has_33([1, 3, 1, 3]) → False\n",
+    "    has_33([3, 1, 3]) → False"
    ]
   },
   {
@@ -469,12 +471,16 @@
    },
    "outputs": [],
    "source": [
-    "def laughter(pattern,text):\n",
-    "    out = 0\n",
-    "    for x in range(len(text)-2):\n",
-    "        if text[x:x+len(pattern)] == pattern:\n",
-    "            out += 1\n",
-    "    return out"
+    "def has_33(nums):\n",
+    "    for i in range(0, len(nums)-1):\n",
+    "      \n",
+    "      # nicer looking alternative in commented code\n",
+    "      #if nums[i] == 2 and nums[i+1] == 2:\n",
+    "    \n",
+    "      if nums[i:i+2] == [2,2]:\n",
+    "        return True  \n",
+    "    \n",
+    "    return False"
    ]
   },
   {
@@ -495,7 +501,7 @@
    ],
    "source": [
     "# Check\n",
-    "laughter('hah','hahahah')"
+    "has_33([1, 3, 3])"
    ]
   },
   {
@@ -983,7 +989,9 @@
    "cell_type": "markdown",
    "metadata": {},
    "source": [
-    "### Just for fun:\n",
+    "-----\n",
+    "### Just for fun, not a real problem :)\n",
+    "\n",
     "#### PRINT BIG: Write a function that takes in a single letter, and returns a 5x5 representation of that letter\n",
     "    print_big('a')\n",
     "    \n",