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14. Longest Common Prefix
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import scala.util.control.Breaks._
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object Solution {
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def longestCommonPrefix(strs: Array[String]): String = {
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if (strs.isEmpty) {
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return ""
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}
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var prefix = strs(0)
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for (i <- 1 until strs.length) {
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val str = strs(i)
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var k = 0;
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breakable {
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while (k < math.min(prefix.length, str.length)) {
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if (prefix(k) != str(k)) {
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break
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}
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k += 1
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}
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}
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prefix = prefix.substring(0, k)
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}
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return prefix;
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}
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}

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