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刘军
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doc/ms/ms.md

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@@ -71,4 +71,5 @@ dp(i, j)=min(dp(i−1, j), dp(i−1, j−1), dp(i, j−1))+1
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此外,还需要考虑边界条件。如果 i 和 j 中至少有一个为 0,则以位置 (i, j) 为右下角的最大正方形的边长只能是 1,因此 dp(i, j)=1
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![](../../res/ms/1.png)

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