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fix go solution for "group-anagrams" to be optimal #2470

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fix go solution for "group-anagrams" to be optimal #2470

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fix go solution for "group-anagrams" to be optimal 
implement using letter count array as a key instead
of a sorted string, according to the video solution.
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@hiendevt
hiendevt committed May 12, 2023
commit f282f89f807ab16f6696c711faa9a85a649d3f7e
19 changes: 8 additions & 11 deletions go/0049-group-anagrams.go
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Original file line number Diff line number Diff line change
@@ -1,15 +1,10 @@
package main

import (
"sort"
"strings"
)

func groupAnagrams(strs []string) [][]string {
kb := make(map[string][]string)
kb := make(map[[26]byte][]string)

for _, str := range strs {
key := sortString(str)
key := countLetters(str)
if _, ok := kb[key]; !ok {
kb[key] = []string{}
}
Expand All @@ -26,8 +21,10 @@ func groupAnagrams(strs []string) [][]string {
return res
}

func sortString(str string) string {
strArr := strings.Split(str, "")
sort.Strings(strArr)
return strings.Join(strArr, "")
func countLetters(str string) [26]byte {
letterCount := [26]byte{}
for _, letter := range str {
letterCount[letter-'a']++
}
return letterCount
}