fix/209: clean up redundant code

Author: novahe

leetcode/0209.Minimum-Size-Subarray-Sum/209. Minimum Size Subarray Sum.go

@@ -1,24 +1,16 @@
 package leetcode
 
-func minSubArrayLen(s int, nums []int) int {
-	n := len(nums)
-	if n == 0 {
-		return 0
-	}
-	left, right, res, sum := 0, -1, n+1, 0
-	for left < n {
-		if (right+1) < n && sum < s {
-			right++
-			sum += nums[right]
-		} else {
+func minSubArrayLen(target int, nums []int) int {
+	left, sum, res := 0, 0, len(nums)+1
+	for right, v := range nums {
+		sum += v
+		for sum >= target {
+			res = min(res, right-left+1)
 			sum -= nums[left]
 			left++
 		}
-		if sum >= s {
-			res = min(res, right-left+1)
-		}
 	}
-	if res == n+1 {
+	if res == len(nums)+1 {
 		return 0
 	}
 	return res

website/content/ChapterFour/0200~0299/0209.Minimum-Size-Subarray-Sum.md

@@ -34,30 +34,29 @@ If you have figured out the O(n) solution, try coding another solution of which
 
 package leetcode
 
-func minSubArrayLen(s int, nums []int) int {
-	n := len(nums)
-	if n == 0 {
-		return 0
-	}
-	left, right, res, sum := 0, -1, n+1, 0
-	for left < n {
-		if (right+1) < n && sum < s {
-			right++
-			sum += nums[right]
-		} else {
+func minSubArrayLen(target int, nums []int) int {
+	left, sum, res := 0, 0, len(nums)+1
+	for right, v := range nums {
+		sum += v
+		for sum >= target {
+			res = min(res, right-left+1)
 			sum -= nums[left]
 			left++
 		}
-		if sum >= s {
-			res = min(res, right-left+1)
-		}
 	}
-	if res == n+1 {
+	if res == len(nums)+1 {
 		return 0
 	}
 	return res
 }
 
+func min(a int, b int) int {
+	if a > b {
+		return b
+	}
+	return a
+}
+
 ```