@ts-ignore not emitted to d.ts

[shaunc]

TypeScript Version: 2.6.1
Code

I have a class deriving from a class in another package, which uses a too general type for an attribute, which I want to override. I can using @ts-ignore. However, the d.ts does not contain the @ts-ignore so another package using this package will not compile.

E.g. in foo.ts

    // @ts-ignore
    class Foo extends Bar { ... }

Expected behavior:

in foo.d.ts:

  // @ts-ignore
  declare class Foo extends Bar { ... }

Actual behavior:

in foo.d.ts:

  declare class Foo extends Bar

which triggers an error.

[mhegazy]

@ts-ignore silences the error that would have been reported otherwise. it has no semantic meaning. It does not make senses to include it in a .d.ts. as a matter of fact, it is wrong to do so.

The correct fix is to update your dependency definition.

[typescript-bot]

Automatically closing this issue for housekeeping purposes. The issue labels indicate that it is unactionable at the moment or has already been addressed.

[shaunc]

The correct fix is to update your dependency definition.

The problem is that I am not in control of the dependency definition. I thought that directly using a .ts file internally and using .d.ts + .js should result in the same compiler behavior. (In other words, .d.ts + .js + .js.map should correspond 1-1 to original .ts.) From an operational point of view, @ts-ignore does have meaning, as it results in an observable different in build tool operation?

Of course I could do something like class Foo extends Bar as any -- but this seems like a much worse hack than using \\ @ts-ignore -- indeed I would have thought that conscribing any hacks as much as possible was exactly the purpose of @ts-ignore.

If it is indeed a useful feature to use within a package (I know there could be argument about that, but I assume its moot, as you indeed do support @ts-ignore), is there a good reason that it should not be used when consuming another package?