Bug Report for permutation-string

[rahme007]

Bug Report for https://neetcode.io/problems/permutation-string

The second solution (C++) with a hash table should have s1.length() as its inner loop. Might be present in other coding environment

Corrected

    int need = count1.size();
    for (int i = 0; i < s2.length(); i++) {
        unordered_map<char, int> count2;
        int cur = 0;
        for (int j = i; j < s1.length(); j++) { // corrected the s1.length()
            char c = s2[j];
            count2[c]++;

[Srihari2222]

In this Second Solution, we are iterating on every substring of s2 which makes us to iterate on only s2 using nested loops rather than s1 and s2.