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42 changes: 42 additions & 0 deletions python/0261-graph-valid-tree.py
Original file line number Diff line number Diff line change
Expand Up @@ -29,3 +29,45 @@ def dfs(i, prev):
return True

return dfs(0, -1) and n == len(visit)



# alternative solution via DSU O(ElogV) time complexity and
# save some space as we don't recreate graph\tree into adjacency list prior dfs and loop over the edge list directly
class Solution:
"""
@param n: An integer
@param edges: a list of undirected edges
@return: true if it's a valid tree, or false
"""
def __find(self, n: int) -> int:
while n != self.parents.get(n, n):
n = self.parents.get(n, n)
return n

def __connect(self, n: int, m: int) -> None:
pn = self.__find(n)
pm = self.__find(m)
if pn == pm:
return
if self.heights.get(pn, 1) > self.heights.get(pm, 1):
self.parents[pn] = pm
else:
self.parents[pm] = pn
self.heights[pm] = self.heights.get(pn, 1) + 1
self.components -= 1

def valid_tree(self, n: int, edges: List[List[int]]) -> bool:
# init here as not sure that ctor will be re-invoked in different tests
self.parents = {}
self.heights = {}
self.components = n

for e1, e2 in edges:
if self.__find(e1) == self.__find(e2): # 'redundant' edge
return False
self.__connect(e1, e2)

return self.components == 1 # forest contains one tree