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Description
This has been brought up several times on the mailing lists. As a specific example
sage: assume(x>0)
sage: solve([x^2-1],x)
[x == -1, x == 1]
At the very least, we could probably filter out the "solutions" that violate the assumptions.
sage: [all(a.subs(s) for a in assumptions()) for s in solve(x^2-1==0, x)]
[False, True]
Component: calculus
Author: Robert Bradshaw
Reviewer: Burcin Erocal
Merged: sage-4.3.3.alpha0
Issue created by migration from https://trac.sagemath.org/ticket/6515